We got to take a look at a few different real life problems using simple machines.
Simple Machines: Lever
EX 1:
A first class lever, in static equilibrium, has a 50 lb resistance forces and 15 lb effort force. The lever's effort force is located 4 ft from the fulcrum.
1. Sketch and annotate lever system described above
2. Calculate:
Actual Mechanical Advantage (AMA)
AMA= Force Resistance/Force Effort
AMA= 50 lbs/15 lbs
AMA= 3.33
3. Static Equilibrium Calculations:
DR= Distance of Resistance Force
M= moment (Force x distance)
Moment Effort + Moment Resistance
-->
∑
-->MFulcrum= 0
(15 lbs)(4 ft) + (50 lbs)(DR)= 0
50 lbs(DR) = 60 lbs/ft
DR= 1.2 ft
EX 2:
A wheel barrow is used to lift a 200 lb load. The length from the wheel axle to the center of the load is 2 ft. The length from the wheel and axle to the effort is 5 ft.
1. Illustrate and annotate lever system described above
A wheel barrow is used to lift a 200 lb load. The length from the wheel axle to the center of the load is 2 ft. The length from the wheel and axle to the effort is 5 ft.
1. Illustrate and annotate lever system described above
2. Calculate:
Ideal Mechanical Advantage (IMA)
IMA= Distance(effort force)/Distance(resistant force)
IMA= 5 feet/ 2 feet
IMA= 2.5
3. Static Equilibrium Calculations:
FE= Force of Effort Force
M= moment (Force x distance)
Moment Effort + Moment Resistance
EX 3:
IMA= Distance(effort force)/Distance(resistant force)
IMA= 5 feet/ 2 feet
IMA= 2.5
3. Static Equilibrium Calculations:
FE= Force of Effort Force
M= moment (Force x distance)
Moment Effort + Moment Resistance
∑
MFulcrum= 0
(200lbs)(2ft) + (5ft)(FE)= 0
5ft (FE) = 400 lbs/ft
FE= 80 lbs
EX 3:
A medical technician uses a pair of 4 inch long tweezers to remove a wood sliver from a patient. The technician is applying 1 lb of squeezing force to the tweezers. If more than 1/5 lb of force is applied to the sliver, it will break and become difficult to remove.
1. Sketch and annotate lever system described above
2. Calculate:
Actual Mechanical Advantage (AMA)
AMA= Force Resistance/Force Effort
AMA= 1 lb/ (1/5) lb
AMA= 0.2
3. Static Equilibrium Calculations:
DR= Distance of Effort Force
M= moment (Force x distance)
Moment Effort + Moment Resistance
∑
MFulcrum= 0
(4 in)(1/5 lb) + (1 lb)(DE)= 0
1 lb(DE) = (4/5) lb/in
DE= 0.8 in
Simple Machines: Pulley
EX 1:
A construction crew lifts approximately 560 lb of material several times during a day from a flatbed truck to a 32 ft rooftop. A block and tackle system with 50 lb of effort force is designed to lift the materials.
1. Calculate:
AMA= Force Resistance/Force Effort
AMA= 560 lb/50 lb
AMA= 11.2
2. How many supporting strands will be needed in the pulley system?
2 x(# of moveable pulleys) + 1(if changing direction)= # of strands
(2 x 4) +1= 9 strands
Anymore?
ReplyDeleteAnymore what?
Deleteare you still alive??
Deletethere are more problems
ReplyDeleteDammit Lauren where are the other problems
ReplyDeletethe wheel and axle for example
ReplyDeleteI love you whoever you are
ReplyDeleteI'm still confuse on how exactly you got 9 strands, where did you manage to get 4 moveable pulleys?
ReplyDeleteUse the actual mechanical advantage formula(resistance force/effort force) to find the amount of strands. Round your decimal results to the nearest whole number. (11.3 to 12)
DeleteI'm still confuse on how exactly you got 9 strands, where did you manage to get 4 moveable pulleys?
ReplyDeleteI think you did your math wrong. you should have 13 or 12 not 9
ReplyDeleteCan you explain that problem, please.
DeleteFor the pulley question, (560Ib resistance force & 50Ib effort force), how did you come up with the 4 moveable pulleys part. Seems like it came out of nowhere
ReplyDeleteGreat job on explaining I got this
ReplyDelete